WebStartTime-与查询提交给Teradata进行解析时相关的时间戳 FirstStepTime-与执行查询的第一步相关联的时间戳 FirstRespTime-与第一行返回到客户端时相关联的时间戳 StartTime和FirstStep time之间的时间间隔包括解析时间和Teradata的动态工作负载管理器实施的任何工 … Web我試圖從另一個日期中減去一個日期,但有問題: 有人可以澄清下面返回的數字的數字格式嗎 我曾嘗試使用 datediff ,但這會將天數四舍五入到最接近的整數,我需要對數據進行進一步的計算。 四舍五入意味着我的解決方案有點偏離。 在我使用的數據庫版本中,datediff 只需要兩個參數,所以據我 ...
Subtract dates in Teradata Teradata datediff - Web4College
1 Teradata: simply subtract dates: SELECT DATE 'date1' - DATE 'date2'; – Mitch Wheat Nov 19, 2024 at 8:52 This is an approximate age calculation, (current_date - startdate)/365.25, exact age calculation: Cast ( (Months_Between (Current_Date, startdate) / 12) AS smallint) – dnoeth Nov 19, 2024 at 11:19 Add a comment 1 Answer Sorted by: 0 Webdate_diff(unit, timestamp1, timestamp2) → bigint Returns timestamp2 - timestamp1 expressed in terms of unit. MySQL Date Functions The functions in this section use a format string that is compatible with the MySQL date_parse and str_to_date functions. The following table, based on the MySQL manual, describes the format specifiers: [1] marlows jewellery birmingham
Teradata Datediff - MindMajix Community
WebJan 8, 2024 · CREATE MULTISET VOLATILE TABLE yourtable ( ID VARCHAR (3) ,T_DATE TIMESTAMP (0) ,L_DATE TIMESTAMP (0) ,DIFF NUMERIC (6,2) ) PRIMARY INDEX (ID) ON COMMIT PRESERVE ROWS; INSERT INTO yourtable (ID,T_DATE,L_DATE,DIFF) VALUES ('AAA','2024-10-08 17:02:00','2024-10-08 … WebOct 22, 2024 · Teradata subtract one month from current date select ADD_MONTHS (current_date,-1); ADD_MONTHS (Date, -1) 2024-09-25 select current_date - INTERVAL … Web我尝试了DATEDIFF(day,effect\u date,next\u effect\u date),但它返回的是浮动天数。我想要integerI中的结果我编辑了我的答案,解释了为什么DATEDIFF输出是浮点值。 If the repository is using Oracle or DB2, the return value is a floating point number. If the repository is using DB2, the server assumes ... marlow sl7 2ft